(5x+4)(x+1)=2x(3x+5)-(x^2+x-4)

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Solution for (5x+4)(x+1)=2x(3x+5)-(x^2+x-4) equation: 



(5x+4)(x+1)=2x(3x+5)-(x^2+x-4)

We move all terms to the left:

(5x+4)(x+1)-(2x(3x+5)-(x^2+x-4))=0

We multiply parentheses ..

(+5x^2+5x+4x+4)-(2x(3x+5)-(x^2+x-4))=0



We calculate terms in parentheses: -(2x(3x+5)-(x^2+x-4)), so:

2x(3x+5)-(x^2+x-4)

We multiply parentheses

6x^2+10x-(x^2+x-4)

We get rid of parentheses

6x^2-x^2+10x-x+4

We add all the numbers together, and all the variables

5x^2+9x+4

Back to the equation:

-(5x^2+9x+4)



We get rid of parentheses

5x^2-5x^2+5x+4x-9x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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